VITEEE 19 If y=tan1 (4x/15x2)tan1 (23x/32x), then (dy/dx)= (A) (1/125x2)(2/1x2) (B) (2/125x2)(2/1x2) (5/125x2) (D) (1/125x2) CheFind dxdy , if y=sec −1 2x 2−11 ,0<x<KCET 12 If y= tan1 ( (1/1xx2)) tan1 ( (1/x22x3)) tan1( (1/x25x7)) dotsn terms then y'(0) is (A) (π/2) (B) (n2/1n2) (n2/1
Solution Of Differential Equation X 2 1 2 Dy Dx 2x X
